Run2 python docx

Advanced DOCX Templating via Direct XML

While the python-docx library is excellent for creating and reading Word documents, it struggles with replacing text placeholders (e.g., {{PLACEHOLDER}}) that have been split across multiple Run (<w:r>) elements due to formatting or spellcheck artifacts in Word.

The Problem

When a user types {{COMPANY_NAME}}, Word often saves it internally as:

<w:r><w:t>{{COMP</w:t></w:r><w:r><w:rPr><w:b/></w:rPr><w:t>ANY_NAME}}</w:t></w:r>

If you use python-docx to read .text from the paragraph, you get the full string, but replacing it and assigning back to paragraph.text destroys all the <w:rPr> (run formatting) properties in that paragraph.

The Solution: Regex over XML

By treating the .docx as a ZIP file, we can read the word/document.xml, word/header1.xml, etc., and apply regular expressions that ignore the XML tags interleaved between our placeholder characters.

1. Building the Regex

To match a placeholder like {{VAR}} regardless of how many tags interrupt it:

import re

def build_regex(var_name):
    # Matches {{var_name}} allowing any <tag> sequences between characters
    pattern = r'\{' + r'(?:<[^>]+>)*' + r'\{' + r'(?:<[^>]+>)*'
    for char in var_name:
        pattern += re.escape(char) + r'(?:<[^>]+>)*'
    pattern += r'\}' + r'(?:<[^>]+>)*' + r'\}'
    return pattern

2. Safely Replacing Matches

When we find a match, we clear the text content inside the matched block (to remove the old placeholder text) but preserve ALL the XML tags. We then inject the replacement string into the first text node (<w:t>). This preserves formatting properties perfectly.

def replace_match(m, replacement=''):
    matched_text = m.group(0)
    # Split text and tags
    parts = re.split(r'(<[^>]+>)', matched_text)
    
    # Clear all actual text fragments
    for i in range(len(parts)):
        if not parts[i].startswith('<'):
            parts[i] = ''
            
    res = ''.join(parts)
    # Inject replacement text just before the first closing text tag (or at start if none)
    if replacement:
        if '</w:t>' in res:
            res = res.replace('</w:t>', replacement + '</w:t>', 1)
        else:
            res = replacement + res
    return res

3. Handling Conditional Blocks

If you have a conditional block like {{IF_RELOCATION}}...{{END_IF_RELOCATION}}:

• If True: Find and replace {{IF_RELOCATION}} and {{END_IF_RELOCATION}} with an empty string using the above method. This removes the markers but keeps the content.
• If False: Build a regex that spans from the start marker to the end marker using .*? with re.DOTALL, and replace the entire match with an empty string using replace_match(m, ''). This safely empties the text between the markers, leaving the XML structure intact (creating an empty paragraph or section).

# To remove a block completely
block_regex = build_regex('IF_RELOCATION') + r'.*?' + build_regex('END_IF_RELOCATION')
xml_content = re.sub(block_regex, lambda m: replace_match(m, ''), xml_content, flags=re.DOTALL)

4. Updating the DOCX File

Use zipfile to read the template, process .xml files, and write to a new .docx.

import zipfile

def process_docx(input_path, output_path, variables):
    with zipfile.ZipFile(input_path, 'r') as zin:
        with zipfile.ZipFile(output_path, 'w', compression=zipfile.ZIP_DEFLATED) as zout:
            for item in zin.infolist():
                content = zin.read(item.filename)
                # Apply replacements to body, headers, and footers
                if item.filename.endswith('.xml') and ('word/document' in item.filename or 'word/header' in item.filename or 'word/footer' in item.filename):
                    content_str = content.decode('utf-8')
                    # Apply your re.sub logic here...
                    content = content_str.encode('utf-8')
                zout.writestr(item, content)

This is the most reliable way to maintain corporate branding, strict formatting, and complex tables in templated Word documents!